Write down the slope of the straight line-of-best-fit from your graph (Make sure to use the correct units.) Slope
=
q,
q,
n=-1,756\times 10^(3) (Kelun )
Using the value you obtained for the slope, calculate the molar heat of vaporization,
\Delta H_(vap )
, in kJ .
\Delta H_(vap )=
q,
Neatly show your work.
\Delta H_(rap )=-(-1.1756\times 10^(3)(K))\times 2,303\times 8.31(J)/(m)od.k
=33606,21(J)/(m)ol