What is the maximum flow rate through the pipe shown in Fig. P7.129 if the elevation difference of the reservoir surfaces is 80m ? Solution: 1. Use an average value of e, so e=mm; 2. Relative roughness ?= 3. Assuming a relative large Re so we can use the horizontal portion of the line on Moody chart, thus f can be found nearly f= 4. There are in

Question

What is the maximum flow rate through the pipe shown in Fig. P7.129 if the elevation difference of the reservoir surfaces is

80 m

? Solution: 1. Use an average value of

e

, so

e = mm

; 2. Relative roughness

? =

3. Assuming a relative large Re so we can use the horizontal portion of the line on Moody chart, thus

f

can be found nearly

f =

4. There are in total hydraulic fittings, total energy loss is

0 h_{f} = \frac{v ^{2}}{2 g};

? h_{m} = \frac{v ^{2}}{2 g};

5. Thus, for the elevation difference given, velocity of the flow in the pipe is

v = m / s

6. Hence, the flow rate is

Q = m^{3} / s

7. Check the Re

= \times 1 0^{6}

. This is sufficiently large.

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