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(Solved): Use the Limit Comparison Test to determine the convergence or divergence of the series. \[ \lim _{n ...
Use the Limit Comparison Test to determine the convergence or divergence of the series. \[ \lim _{n \rightarrow \infty} \frac{\sum_{n=0}^{\infty} \frac{1}{\sqrt{n^{2}+4}}}{\frac{1}{\sqrt{n^{2}+4}}}=L>0 \] converges diverges
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given ² ?an=1(n²+4)12 let ?bn=1n which is a divergent series u