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(Solved): Two \( 2.20 \mathrm{~cm} \times 2.20 \mathrm{~cm} \) plates that form a parallel plate capacitor a ...



Two \( 2.20 \mathrm{~cm} \times 2.20 \mathrm{~cm} \) plates that form a parallel plate capacitor are charged to \( \pm 0.708

Two \( 2.20 \mathrm{~cm} \times 2.20 \mathrm{~cm} \) plates that form a parallel plate capacitor are charged to \( \pm 0.708 \mathrm{nC} \). What is the electric field strength inside the capacitor if the specing between the plates is \( 1.50 \mathrm{~mm} \) ? Express your answer with the appropriate units. Correct Here we learn how to calculate the strength of the electnc field in a capacitor - Parta What is potential difterence across the capacitor it the spacing between the plates is \( 150 \mathrm{~mm} \) ? Express your answer with the appropriate units. - Part C What is the electric field strength inside the capacitor if the spacing between the plates is \( 3.00 \mathrm{~mm} \) ? Express your answer with the appropriate units. - Part D What is the potential difference across the capacitor if the spacing between the plates is \( 3.00 \mathrm{~mm} \) ? Express your answer with the appropriate units.


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Given plate area 2.2cm×2.2cm Charge on the plate q=0.708nC Part A Spacing between plate 1.5m
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