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(Solved): three spiders are resting on the vertices of a triangular web. The sides of the triangular web have ...



three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of a equals zero. 42M, as the pick that in the figure. Two other spiders (S1 and S3) have +8.0 mC charge, while the other (S2) has -8.0mC charge.

Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of \( a=0.42 \ma
Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of \( a=0.42 \mathrm{~m} \), as depicted in the figure. Two of the spiders \( \left(S_{1}\right. \) and \( S_{3} \) ) have \( +8.0 \mu \mathrm{C} \) charge, while the other \( \left(S_{2}\right) \) has \( -8.0 \mu \mathrm{C} \) charge. (a) What are the magnitude and direction of the net force on the third spider \( \left(S_{3}\right) \) ? magnitude \( \mathrm{N} \) direction \( { }^{\circ} \) counterclockwise from the \( +x \)-axis (b) Suppose the third spider \( \left(S_{3}\right) \) moves to the origin. Would the net force on the third spider \( \left(S_{3}\right) \) be greater than, less than, or equal to the magnitude found in part (a)? greater than in part (a) less than in part (a) equal to the part (a) (c) What are the magnitude and direction of the net force on the third spider \( \left(\mathrm{S}_{3}\right. \) ) when it is resting at the origin? magnitude How do you find the magnitude of the electric force? How do you find the total net force? \( \mathrm{N} \) direction \( \sim{ }^{\circ} \) counterclockwise from the \( +x \)-axis


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Solution:- PLEASE LIKE IT. i consider that, you already solve a , b . if
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