The probability of having an offspring with both the dominant phenotypes for both genes is equal to the product of the individual probabilities. This means, if the probability of having a dominant phenotype for both traits would be Multiple Choice
(3)/(4)\times (1)/(4)=(3)/(16)
(4)/(4)\times (4)/(4)=(16)/(16)
(1)/(2)\times (1)/(2)=(1)/(4)
(3)/(4)\times (3)/(4)=(9)/(16)
.