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(Solved): The height, in feet, of an object shot upwards into the air with an initial velocity, in feet per se ...



The height, in feet, of an object shot upwards into the air with an initial velocity, in feet per second, of vi, after t seconds is given by the formula: 

1 ^ + -791 - = y

Use the equation above to answer questions about a model rocket is launched from the ground into the air with an initial velocity of 352 feet per second. Use the graph below to help answer the questions.

Height in Feet
H
Starting
Point
Highest
Point
Time in Seconds
Landing
Point
t

Part 1: Create the equation for the height of the rocket after t seconds.

Part 2: Find the time it takes for the rocket to reach a height of 0. Interpret both solutions.

Part 3: Find the time it takes to reach the top of its trajectory.

Part 4: Find the maximum height.

Part 5: Find the time it takes to reach a height of 968 feet. Round your answer to the nearest tenth.

 

(Please explain each step, I will give thumbs up regardless, but i'd like to understand each step, thank you!) 

1 ^ + -791 - = y Height in Feet H Starting Point Highest Point Time in Seconds Landing Point t


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