(Solved): The gas-phase reaction between methanol (A) and acetic acid (B) to form methyl acetate (C) and wat ...

The gas-phase reaction between methanol (A) and acetic acid (B) to form methyl acetate (C) and water (D) CH3OH + CH3COOH CH3OOCCH3 + H?O takes place in a batch reactor and proceeds to equilibrium. When the reactor mixture comes to equilibrium, the mole fractions of the four reactive species are related by a reaction equilibrium constant ?? ?? = Keq = 2.87 YA YB The feed to the reactor consists of nao, n?o, nco, nDo and nio gram moles of A, B, C, D and an inert gas I respectively. a. If nÃO = 1.400 ngo, and all other input quantities are 0.0, what is the equilibrium fractional conversion of A? i 0.775 b. It is desired to produce 60.0 moles of methyl acetate starting with 63.0 moles of methanol, an unknown amount of acetic acid, and no other components. If the reaction proceeds to equilibrium, how much acetic acid must be fed? Required acetic acid: i 359.4 mol