(Solved): The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bic ...

The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate \( \left(\mathrm{NaHCO}_{3}\right) \) reacting with one mole of hydrochloric acid ( \( \mathrm{HCl}) \) to produce one mole of carbonic acid \( \left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) \), and one mole of sodium chloride \( (\mathrm{NaCl}) \). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol NaHCO and \( 8 \mathrm{~mol} \mathrm{HCl} \). moles of carbonic acid : mol Which of the two heactants limits the number of moles of \( \mathrm{H}_{2} \mathrm{CO}_{3} \) that can be made? \( \mathrm{NaHCO}_{3} \) \( \mathrm{HCl} \) How much excess reactant remains after the reaction? excess reactant : mol