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(Solved): The figure shows a thin plastic rod of length L=18.7cm and uniform charge 16.2 fC . (a) In terms of ...
The figure shows a thin plastic rod of length L=18.7cm and uniform charge 16.2 fC . (a) In terms of distance d, charge density \lambda and \epsi _(0)
find an expression for the electric potential at point P_(1). Next, substitute variable x for d and find an expression for the magnitude of the
component E_(x) of the electric field at P_(1) (in terms of d and other variables). (b) What is the direction of E_(x) relative to the positive
direction of the x axis? (c) What is the value of E_(x) at P_(1) for x=d=6.09cm ? (d) From the symmetry in figure determine E_(y) at P_(1).
(a)
V=(\lambda )/(4\pi \epsi _(0))ln(1+(d)/(L)) and E_(x)=(\lambda d)/(4\pi \epsi _(0)L(d+L))
V=(\lambda )/(2\pi \epsi _(0))ln(1+(L)/(d)) and E_(x)=(\lambda L)/(2\pi \epsi _(0)d(d+L))
V=(\lambda )/(2\pi \epsi _(0))ln(1+(d)/(L)) and E_(x)=(\lambda d)/(2\pi \epsi _(0)L(d+L))
V=(\lambda )/(4\pi \epsi _(0))ln(1+(L)/(d)) and E_(x)=(\lambda L)/(4\pi \epsi _(0)d(d+L))
(b) Number
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(c) Number
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(d) Number
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