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(Solved): The figure below shows a 120 -turn square coil rotating about a vertical axis at at in 1,610 rev ...
The figure below shows a 120 -turn square coil rotating about a vertical axis at at ω in 1,610 rev/min. The length of a side of the coil is 20.0 cin. The horizontal component of the Earth's magnetic field at the coil's location is equal to 2.00×10−5T. (a) What is the magnitude of the maximum emf (in mV) induced in the coil by the Earth's magnetic field? mV (b) What is the orientation of the coil with respect to the magnetic field when the maximum emf occurs? The plane of the coil is perpendicular to the magnetic field. The plane of the coil is parallel to the magnetic field: The plane of the coil is oriented 45∘ with respect to the magnetic field.
Solution:Given:N = number of turns of wire = 120s = side of square coil = 20.0 cm = 0.200 mB = horizontal component of Earth's magnetic field = 2.00 x 10-5 T? = rotational speed of coil = 1610 rpmE0 = maximum emf induced in the coil (in mV) = ?What is the orientation of the coil with respect to the magnetic field when the maximum emf occurs?Choose the correct option:A) The plane of the coil is perpendicular to the magnetic field.B) The plane of the coil is parallel to the magnetic field:C) The plane of the coil is oriented 45o with respect to the magnetic field.In this step we have collected the input data and also formulated the question precisely.