The curvature kappa of a curve r(t) at t is given by kappa =|(dT)/(ds)| where T is the unit tangent vector and s is the arclength parameter. Taking N to be the unit normal to the curve, derive the following equation (dT)/(ds)= kappa N can you also explain how to get the final answer or what does it look like

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The curvature  kappa  of a curve r(t) at t is given by  kappa =|(dT)/(ds)| where T is the unit tangent vector and s is the arclength parameter. Taking N to be the unit normal to the curve, derive the following equation (dT)/(ds)= kappa N can you also explain how to get the final answer or what does it look like

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(Solved): The curvature \kappa of a curve r(t) at t is given by \kappa =|(dT)/(ds)| where T is the unit tan ...

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