(Solved): Q2. A student investigated the reactions of copper carbonate and copper oxide with dilute hydrochl ...

Q2. A student investigated the reactions of copper carbonate and copper oxide with dilute hydrochloric acid. In both reactions one of the products is copper chloride. (a) Describe how a sample of copper chloride crystals could be made from copper carbonate and dilute hydrochloric acid. Page 2 of 48 (b) A student wanted to make \( 11.0 \mathrm{~g} \) of copper chloride. The equation for the reaction is: \[ \mathrm{CuCO}_{3}+2 \mathrm{HCl}-\mathrm{CuCl}_{2}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \] Relative atomic masses, \( A_{i}: \mathrm{H}=1 ; \mathrm{C}=12 ; \mathrm{O}=16 ; \mathrm{Cl}=35.5 ; \mathrm{Cu}=63.5 \) Calculate the mass of copper carbonate the student should react with dilute hydrochloric acid to make \( 11.0 \mathrm{~g} \) of copper chloride. Mass of copper carbonate \( = \) 2 (c) The percentage yield of copper chloride was \( 79.1 \% \). Calculate the mass of copper chloride the student actually produced. Actual mass of copper chloride produced \( = \) 9 (d) Look at the equations for the two reactions: Reaction \( 1 \mathrm{CuCO}(5)+2 \mathrm{HCl}_{(a q)}-\mathrm{CuCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{D})+\mathrm{CO}_{2}(\mathrm{~g}) \) Reaction \( 2 \quad \mathrm{CuO}(5)+2 \mathrm{HCl}_{2}(\mathrm{aq})-\mathrm{CuCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \) Reactive formula masses: \( \mathrm{CuO}=79.5 ; \mathrm{HCl}=36.5 ; \mathrm{CuCl}_{2}=134.5 ; \mathrm{H}_{4} \mathrm{O}=18 \) The percentape atom economy for a reaction is calculated using: