Post-Lab Question 10 Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to the balanced equation below: 3AgNO_(3)(aq)+1AlCl_(3)(aq)-1Al(NO_(3))_(3)(aq)+3AgCl(s) Wayne reacted 1.644g of aluminum chloride with an excess amount of silver nitrate. Based on the balanced chemi

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Post-Lab Question 10 Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to the balanced equation below:

3AgNO_(3)(aq)+1AlCl_(3)(aq)->1Al(NO_(3))_(3)(aq)+3AgCl(s)

Wayne reacted

1.644g

of aluminum chloride with an excess amount of silver nitrate. Based on the balanced chemical equation above and the mass of aluminum chloride, determine Wayne's theoretical yield (in grams) of solid silver chloride. Molar mass silver nitrate:

169.87(g)/(m)ol

Molar mass aluminum chloride:

133.34(g)/(m)ol

Molar mass silver chloride:

143.32(g)/(m)ol

Report your answer to accurate significant figures.

g

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