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(Solved): Please show calculations and explanations. In humans, hemophilia A(h) and red-green color blindnes ...



In humans, hemophilia \( \mathrm{A}(h) \) and red-green color blindness \( (c) \) are two \( \mathrm{X} \)-linked recessive dPlease show calculations and explanations.

In humans, hemophilia and red-green color blindness are two -linked recessive diseases. The and loci are separated by only . Let and represent the wildtype alleles for hemophilia and color-blindness, respectively. In the pedigree shown here, individual I-2 is affected by both disorders. What is the probability that his Hemophilia = Color blind


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Since individual I-2 is affected by both hemophilia and color blindness, this means that he must carry two copies of the recessive alleles for both h and c. Thus, his genotype must be XhXhCc, since he is male and only has one X chromosome.
To calculate the probability that his great grandson (IV-1) is color-blind but not hemophiliac, we need to first determine the genotype of IV-1's mother (III-2), since she is the carrier of the X chromosome that is passed down to IV-1.
Since III-2 is the daughter of I-2 and is not affected by either disorder, she must be a carrier for both h and c, but not have the disorders herself. Thus, her genotype must be XHXhXc, meaning she has one wild-type X chromosome and one X chromosome with the h and c recessive alleles.
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