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(Solved): Please show calculations and explanations.
In humans, hemophilia A(h) and red-green color blindnes ...
Please show calculations and explanations.
In humans, hemophilia A(h) and red-green color blindness (c) are two X-linked recessive diseases. The h and c loci are separated by only 4cM. Let H and C represent the wildtype alleles for hemophilia and color-blindness, respectively. In the pedigree shown here, individual I-2 is affected by both disorders. What is the probability that his 1-year old great grandson (IV-1) is color-blind but not hemophiliac? ?= Hemophilia = Color blind
Since individual I-2 is affected by both hemophilia and color blindness, this means that he must carry two copies of the recessive alleles for both h and c. Thus, his genotype must be XhXhCc, since he is male and only has one X chromosome.To calculate the probability that his great grandson (IV-1) is color-blind but not hemophiliac, we need to first determine the genotype of IV-1's mother (III-2), since she is the carrier of the X chromosome that is passed down to IV-1.Since III-2 is the daughter of I-2 and is not affected by either disorder, she must be a carrier for both h and c, but not have the disorders herself. Thus, her genotype must be XHXhXc, meaning she has one wild-type X chromosome and one X chromosome with the h and c recessive alleles.