Let
a_(n)=(6n)/(8n 1).
(a) Determine whether
{a_(n)} is convergent or divergent. If it is convergent, find the limit. (If the quantity diverges, enter DIVERGES.)
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(b) Determine whether
\sum_(n=1)^(\infty ) a_(n) is convergent.
Converges; the limit of the terms
a_(n) is a constant as
n goes to
\infty .
Converges; the series is a constant multiple of a geometric series
Diverges; the series is a constant multiple of the harmonic series.
Diverges; the limit of the terms
a_(n) is not 0 as
n goes to
\infty .
Diverges; the sequence
a_(n) diverges as
n goes to
\infty .
