(Solved): nbutane change to isobutane \( n \)-Butane \( \left(n-\mathrm{C}_{4} \mathrm{H}_{10}\right) \) is co ...

\( n \)-Butane \( \left(n-\mathrm{C}_{4} \mathrm{H}_{10}\right) \) is converted to isobutane \( \left(i-\mathrm{C}_{4} \mathrm{H}_{10}\right) \) in a continuous isomerization reactor that operates isothermally at \( 147^{\circ} \mathrm{C} \). The feed to the reactor contains 92 \( \mathrm{mol} \% \mathrm{n} \)-butane, \( 6 \mathrm{~mol} \% \) isobutane and \( 2 \mathrm{~mol} \% \mathrm{HCl} \), also at \( 147^{\circ} \mathrm{C} \), and a \( 42 \% \) conversion of \( n \)-butane is achieved. \[ n-\mathrm{C}_{4} \mathrm{H}_{10} \rightarrow i-\mathrm{C}_{4} \mathrm{H}_{10} \] 2 (Note: The reaction takes place with a fixed catalyst. \( \mathrm{HCl} \) is used to enhance the catalysis process; it is not altered or consumed in the reaction) Draw a diagram of the reaction, showing all streams, and solve the following: a. Taking a basis of \( 1 \mathrm{~mol} \) of feed gas, calculate the moles of each component of the feed and product mixtures and the extent of reaction; b. Calculate the standard heat of the (isomerization) reaction \( (\mathrm{kJ} / \mathrm{mol}) \). Then, taking the feed and product species at \( 25^{\circ} \mathrm{C} \) as references, prepare an inlet-outlet enthalpy table and calculate and fill-in the component amounts and specific enthalpies: c. Calculate the required rate of heat transfer to or from the reactor: d. Use your calculated results to determine the heat of the isomerization reaction at \( 147^{\circ} \mathrm{C} \) (Note: Use the data on the following page to solve this problem.) Standard Heat of Formation@25. C [kJ/mol]