(Solved):   Work done by variable forces: A force on a particle depends on position such that \( F(x)= ...

 

Work done by variable forces: A force on a particle depends on position such that \( F(x)=\left(3.00 \mathrm{~N} / \mathrm{m}^{2}\right) x^{2}+(6.00 \mathrm{~N} / \mathrm{m}) x \) for a particle constrained to move along the \( x \)-axis. What work is done by this force on a particle that moves from \( x=0.00 \mathrm{~m} \) to \( x=2.00 \mathrm{~m} \) ? \( -48.0 \mathrm{~J} \) \( 24.01 \) \( 10.0 \mathrm{~J} \) \( 48.0 \mathrm{~J} \) \( 20.0 \mathrm{f} \)