(Solved):   b) Methane reacts with chlorine in the presence of UV light by a free radical substitution ...

 

b) Methane reacts with chlorine in the presence of UV light by a free radical substitution reaction, producing chloromethane and hydrogen chloride as in the following equation: \[ \mathrm{CH}_{4}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow \mathrm{CH}_{3} \mathrm{Cl}(\mathrm{g})+\mathrm{HCl}(\mathrm{g}) \] Write down the mechanism for this reaction. You should include the following steps: (i) Initiation (ii) Propagation (iii) Termination \( (4 \) marks)