(Solved):   #2 pls and thank you Monochromatic light is incident on (and perpendicular to) two slits s ...

 

#2 pls and thank you

Monochromatic light is incident on (and perpendicular to) two slits separated by 0.200 mm, which causes an interference pattern on a screen 513 cm away. The light has a wavelength of 656.3 nm. (a) What is the fraction of the maximum intensity at a distance of 0.600 cm from the central maximum of the interference pattern? I Imax X What is the formula for the intensity of the double-slit interference pattern, for the small angle approximation? Can you write it in terms of the fraction of the maximum intensity? Be sure to convert all lengths to meters before evaluating, and be sure your calculator is in radian mode when finding the cosine. (b) What If? What is the minimum distance (absolute value, in mm) from the central maximum where you would find the intensity to be half the value found in part (a)? B is X 1 Using the same formula from part (a), can you solve for y, the distance from the central maximum, when the ratio half the result from part (a)? Be sure your calculator is in radian mode when finding the inverse cosine. Be careful of units, and be sure your final answer is in mm. mm max