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(Solved): Kuthertords scattering Scattering angle \( \theta, \quad \varphi=90^{\circ}-\ ...



Kuthertords scattering
Scattering angle \( \theta, \quad \varphi=90^{\circ}-\frac{\theta}{2} \)
\( D= \) distance of dosest a???????

Kuthertords scattering Scattering angle \( \theta, \quad \varphi=90^{\circ}-\frac{\theta}{2} \) \( D= \) distance of dosest approach \( =\frac{z t e^{2}}{4 \pi \varepsilon_{0} m v^{2} / 2} \) \( b= \) impact parameter \( =\frac{D}{2} \cot \frac{\theta}{2} \) \( x r= \) distance of \( \alpha \)-particle to nuclens Derive this equation, strow clear steps.


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In Rutherford's scattering experiment, a beam of alpha particles is directed at a thin sheet of gold
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