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(Solved): i really need this Fvaluate the iterated integral by converting to polar coordinates. \[ \int_{0}^{6 ...



i really need this

Fvaluate the iterated integral by converting to polar coordinates.
\[
\int_{0}^{6} \int_{0}^{\sqrt{6 x-x^{2}}} x y d y d x
\]
Use polar coordinates to set up and evaluate the double integral \( \int_{R} \int f(x, y) d A \).
\[
f(x, y)=5 \arctan \frac{
Sketch a graph of the region bounded by the graphs of the equations: Inside the circle \( r=2 \cos (\theta) \) and outside th
Sketch the region \( R \) and evaluate the iterated integral \( \int_{R} \int f(x, y) d A \).
\[
\int_{0}^{8} \int_{y-a}^{0}
Fvaluate the iterated integral by converting to polar coordinates. \[ \int_{0}^{6} \int_{0}^{\sqrt{6 x-x^{2}}} x y d y d x \] Use polar coordinates to set up and evaluate the double integral \( \int_{R} \int f(x, y) d A \). \[ f(x, y)=5 \arctan \frac{y}{x}, R: x^{2}+y^{2} \geq 1, x^{2}+y^{2} \leq 4,0 \leq y \leq x \] \[ d r d t= \] Sketch a graph of the region bounded by the graphs of the equations: Inside the circle \( r=2 \cos (\theta) \) and outside the circle \( r=1 \) Sketch the region \( R \) and evaluate the iterated integral \( \int_{R} \int f(x, y) d A \). \[ \int_{0}^{8} \int_{y-a}^{0} e^{x+y} d x d y+\int_{0}^{8} \int_{0}^{8-y} e^{x+y} d x d y \]


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6. Let the given integral is I=?06?06x?x2xydydx hence we can see that integration region is bounded by
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