(Solved): Hydrogen sulfide burns in oxygen to form sulfur dioxide and water. If sulfur dioxide is being forme ...

Hydrogen sulfide burns in oxygen to form sulfur dioxide and water. If sulfur dioxide is being formed at a rate of \( 0.587814856462 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \), what are the rates of disappearance of hydrogen sulfide and oxygen? Rate of disappearance of \( \mathrm{O}_{2} \) is \( \mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}^{-1} \). Rate of disappearance of \( \mathrm{H}_{2} \mathrm{~S} \) is \( \mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}^{-1} \)