(Solved): glass spheres of density 2450 kg/m and viscosity 15cP rise in a water (density = 1000 kg/m and ...

glass spheres of density 2450 kg/m³ and viscosity 15cP rise in a water (density = 1000 kg/m³ and viscosity = 1.0×10³ Pa's) tank 5m high. The average drop size is 65µm and the volume concentration of oil is 20%. (1) Calculate the free settling velocity! (state assumption and verify it after computing of ut !) (2) Calculate the hindered velocity! (3) Calculate the time required to free water from oil if traveled distance is half he tank's height!. Terminal Velocity PU, Dy Ne- Agip-pi SCOP #D) (PPP) 18p U?= -1.75 K-D de-PD? P 100 EDP (P?P) 18 Pep + (1e)p, D, N Hat -(1-c) Fluidized bed: 41-1 41-4 JP # 150 V (1-² 1.75 g (1-0) ¹ D? AP 150 V (1-1.75² (1-0) + D liye =(1-2)(P?P) (x-XXX-XXX?(1-x?) (x-?)(1-x) E- PH PA-P D? VP?-P DPP DP-P U?A= Appendix: useful equations Dip,-plaed 18 8.D (PPP) 18p 150(1-) D 1.75 Expansion of fided bed ple-ple= Ve 150p K pac 2.4¹ AP APR AP= A? = F - off Ap a... m SA G-AMARE A fy 1-[?-10/0 6140 EM a= a(AP)* A? 2-( D 3y-g F 38-39 B_39-X FX?-%g Ap JH?-D 18 port! - 20 perty-r 2am/A²+ R/A) ²-D²- 18 In (²) shu²³(?-D²1-1 18p la [+]