(Solved): For the circuit shown below, when the push button is pressed: Protection Diode Push button -- 9V Ti ...

For the circuit shown below, when the push button is pressed: Protection Diode Push button -- 9V Time left 0:30:41 +1000?F LED I O a. The LED turns off after the push button is released because of the capacitor is open circuit in DC circuit. O b. Once the battery is on for enough time for the capacitor to be fully charged up to 9 volts, the capacitor now acts as the power source for the circuit, giving power to the LED, so that it stays on for ever even if the push button is released. c. the battery charges the capacitor up with voltage and it gives power to the LED, lighting it. When the push button is released the capacitor now acts as the (temporary) power source for the circuit, giving power to the LED, so that it stays on for a few seconds. Od. The LED remains off because the capacitor is not charged with DC supply voltage. Clear my choice 4700 M