(Solved): Evaluate the following integral using trigonometric substitution. \[ \int \frac{\sqrt{36-x^{2}}}{x} ...

Evaluate the following integral using trigonometric substitution. \[ \int \frac{\sqrt{36-x^{2}}}{x} d x \] What substitution will be the most helpful for evaluating this integral? A. \( x=6 \sec \theta \) B. \( x=6 \sin \theta \) C. \( x=6 \tan \theta \) Rewrite the given integral using this substitution. \[ \int \frac{\sqrt{36-x^{2}}}{x} d x=\int 1 \mid d \theta \] (Simplify your answers. Type exact answers.)