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(Solved): Construct a unit vector that is parallel to \( \vec{A} \). Enter the \( x, y \), and \( z \) compon ...




Construct a unit vector that is parallel to \( \vec{A} \).
Enter the \( x, y \), and \( z \) components of the vector separat
Construct a unit vector that is antiparallel to \( \vec{A} \).
Enter the \( x, y \), and \( z \) components of the vector sep
Construct a unit vector that is parallel to \( \vec{A} \). Enter the \( x, y \), and \( z \) components of the vector separated by commas. \[ A=6.0 \mathrm{i}-5.0 \mathrm{k} \] X Incorrect; Try Again: 3 attempts remaining Part B Construct a unit vector that is antiparaliel to \( \vec{A} \). Enter the \( z, y \), and \( z \) components of the vector separated by commas. Construct a unit vector that is antiparallel to \( \vec{A} \). Enter the \( x, y \), and \( z \) components of the vector separated by commas. Part C Construct two unit vectors that are perpendicular to \( \vec{A} \) and that have no \( y \)-component. Enter the \( x, y \), and \( z \) components of the vectors separated by commas.


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Given that vector A = 6.0 i - 8.0 k Unit vector in the direction parallel to vector A will be given by: a = A/|A| A = 6.0 i + 0 j - 8.0 k |A| = sqrt (6.0^2 + 0^2 + (-8.0)^2) = 10 a = (6.0 i + 0 j - 8.0 k)/10 a = (6.0/10) i + (0/10) j - (8.0/10) k a
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