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(Solved): Consider the reaction of sodium sulfide with oxygen and water. \[ 2 \mathrm{Na}_{2} \mathrm{~S}(\ma ...
Consider the reaction of sodium sulfide with oxygen and water. \[ 2 \mathrm{Na}_{2} \mathrm{~S}(\mathrm{aq})+2 \mathrm{O}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{I}) \longrightarrow \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}(\mathrm{aq})+2 \mathrm{NaOH}(\mathrm{aq}) \] Determine the limiting reactant in a mixture containing \( 170 \mathrm{~g} \) of \( \mathrm{Na}_{2} \mathrm{~S}, 58.6 \mathrm{~g} \) of \( \mathrm{O}_{2} \), and \( \mathbf{2 3 . 4} \mathrm{g}_{2} \) of \( \mathrm{H}_{2} \mathrm{O} \). Calculate the maximum mass (in grams) of sodium thiosulfate, \( \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \), that can be produced in the reaction. The limiting reactant is: \( \mathrm{O}_{2} \) \( \mathrm{Na}_{2} \mathrm{~S} \) \( \mathrm{H}_{2} \mathrm{O} \) Amount of \( \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \) formed \( = \)
Mass of Na2S = 170g Molar mass of Na2S = 142.04 g/mol Number of moles of Na2S = mass /molar mass = (170g)/(142.04 g/mol) = 1.1968 mol = Mass of O2 = 58.6 g Molar mass o