Consider the indefinite integral int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decomposes into the form ax b (c)/(x-3) (d)/(x 3) where a= b= c= d= Integrating term by term, we obtain that int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx=

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Consider the indefinite integral  int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decomposes into the form ax b (c)/(x-3) (d)/(x 3) where a= b= c= d= Integrating term by term, we obtain that  int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx=

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Expert Answer to - Consider the indefinite integral  int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decompo

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Solution for - Consider the indefinite integral  int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decompo

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This an additional answer to - Consider the indefinite integral  int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decompo

(Solved): Consider the indefinite integral \int (6x^(3) 3x^(2)-49x-30)/(x^(2)-9),dx Then the integrand decompo ...

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