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(Solved): CH3OCH2CH(CH3)CH3+2HBr CH3CH2OCH2CH3+HCl (CH3)2CHOCH2CH3+ ...





\( \mathrm{CH}_{3} \mathrm{OCH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{3}+2 \mathrm{HBr} \rightarrow \)
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