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(Solved): Assessment: The following question was given to ChatGPT. Determine what's correct, fix all the mist ...



Assessment: The following question was given to ChatGPT. Determine what's correct, fix all the mistakes, and assign a letter grade: A,B,C,D,F. Let us consider some new definitions. (a) Irreflexive

AAxnot(xRx)

(b) Antitransitivity:

AAx,y,z(xRy^(^())yRz->not(xRz))

Give a relation R on a set A such that it is neither reflexive, symmetric, transitive, antisymmetric, irreflexive nor antitransitive. To create a relation

R

on a set

A

such that it is neither reflexive, symmetric, transitive, antisymmetric, irreflexive, nor antitransitive, we can follow these steps: Reflexive:

R

is not reflexive if there exists at least one element

ainA

such that

(a,a)!inR

. Symmetric:

R

is not symmetric if there exist elements

a,binA

such that

(a,b)inR

but

(b,a)!inR

. Transitive:

R

is not transitive if there exist elements

a,b,cinA

such that

(a,b)inR

and

(b,c)inR

but

(a,c)!inR

. Antisymmetric:

R

is not antisymmetric if there exist elements

a,binA

such that

(a,b)inR

and

(b,a)inR

but

a!=b

. Irreflexive:

R

is not irreflexive if there exists at least one element

ainA

such that

(a,a)inR

.

Antitransitive:

R

is not antitransitive if there exist elements

a,b,cinA

such that

(a,b)inR

and

(b,c)inR

and

(a,c)inR

. Consider the set

A={1,2,3}

. Define the relation

R

on

A

as follows:

R={(1,2),(2,3),(3,1),(1,1)}

Let's check each property: Reflexive:

R

is not reflexive because

(2,2)!inR

and

(3,3)!inR

. Symmetric:

R

is not symmetric because

(1,2)inR

but

(2,1)!inR

. Transitive:

R

is not transitive because

(1,2)inR

and

(2,3)inR

, but

(1,3)!inR

. Antisymmetric:

R

is not antisymmetric because

(1,1)inR

and

(1,1)inR

but

1=1

, so we need another pair to violate this, but for the given pairs, it doesn't. Irreflexive:

R

is not irreflexive because

(1,1)inR

. Antitransitive:

R

is not antitransitive because

(1,2)inR,(2,3)inR

, and

(1,3)!inR

, but we have

(3,1)inR

. Thus, the relation

R={(1,2),(2,3),(3,1),(1,1)}

on the set

A={1,2,3}

satisfies the condition of being neither reflexive, symmetric, transitive, antisymmetric, irreflexive, nor antitransitive.



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