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(Solved): Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensit ...



Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity

I_(0)

, which goes through a circular aperture of diameter

l

Find the intensity of the light on axis (i.e.

x,y=0

). HINT: The integral takes on the following form:

E(0,0,d)=-(i)/(\lambda )∬_(aperture )E(x^('),y^('),0)(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(') =-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')

Then you will want to make the following change of variables:

\xi -=\sqrt(\rho ^('2)+d^(2))

. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field

E_(0)e^(ikd)

to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of

d

) and is equal to the intensity of the initial plane wave.Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity

I_(0)

, which goes through a circular aperture of diameter

l

Find the intensity of the light on axis (i.e.

x,y=0

). HINT: The integral takes on the following form:

E(0,0,d)=-(i)/(\lambda )∬_(aperture )E(x^('),y^('),0)(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(') =-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')

Then you will want to make the following change of variables:

\xi -=\sqrt(\rho ^('2)+d^(2))

. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field

E_(0)e^(ikd)

to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of

d

) and is equal to the intensity of the initial plane wave. Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity

I_(0)

, which goes through a circular aperture of diameter

l

Find the intensity of the light on axis (i.e.

x,y=0

). HINT: The integral takes on the following form:

E(0,0,d)=-(i)/(\lambda )∬_(aperturo )E(x^('),y^('),\theta )(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(') =-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')

Then you will want to make the following change of variables:

\xi -=\sqrt(\rho ^('2)+d^(2))

. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field

E_(0)e^(ikd)

to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of

d

) and is equal to the intensity of the initial plane wave. 5. Repeat Question 3 to find the on-axis intensity after a circular aperture in the Fresnel approximation. HINT: You can make a suitable approximation directly to the answer of Question 3 to obtain the Fresnel approximation. However, you should also perform the integration under the Fresnel approximation for the sake of gaining experience. 6. Repeat Question 3 (or Question 5) to find the on-axis intensity after a circular aperture in the Fraunhofer approximation. HINT: You can make a suitable approximation directly to the answer of Question 5 to obtain the Fraunhofer approximation. However, you should perform the integration under the Fraunhofer approximation for the sake of gaining experience.

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