Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity
I_(0)
, which goes through a circular aperture of diameter
l
Find the intensity of the light on axis (i.e.
x,y=0
). HINT: The integral takes on the following form:
E(0,0,d)=-(i)/(\lambda )∬_(aperture )E(x^('),y^('),0)(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(')
=-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')
Then you will want to make the following change of variables:
\xi -=\sqrt(\rho ^('2)+d^(2))
. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field
E_(0)e^(ikd)
to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of
d
) and is equal to the intensity of the initial plane wave.Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity
I_(0)
, which goes through a circular aperture of diameter
l
Find the intensity of the light on axis (i.e.
x,y=0
). HINT: The integral takes on the following form:
E(0,0,d)=-(i)/(\lambda )∬_(aperture )E(x^('),y^('),0)(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(')
=-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')
Then you will want to make the following change of variables:
\xi -=\sqrt(\rho ^('2)+d^(2))
. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field
E_(0)e^(ikd)
to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of
d
) and is equal to the intensity of the initial plane wave. Apply the Fresnel-Kirchhoff diffraction formula (7.1) to a monochromatic plane wave with intensity
I_(0)
, which goes through a circular aperture of diameter
l
Find the intensity of the light on axis (i.e.
x,y=0
). HINT: The integral takes on the following form:
E(0,0,d)=-(i)/(\lambda )∬_(aperturo )E(x^('),y^('),\theta )(e^(ik\sqrt(x^('2)+y^('2)+d^(2))))/(\sqrt(x^('2)+y^('2)+d^(2)))dx^(')dy^(')
=-(iE_(0))/(\lambda )\int_0^(2\pi ) d\theta ^(')\int_0^((l)/(2)) (e^(ik\sqrt(\rho ^('2)+d^(2))))/(\sqrt(\rho ^('2)+d^(2)))\rho ^(')d\rho ^(')
Then you will want to make the following change of variables:
\xi -=\sqrt(\rho ^('2)+d^(2))
. This will make it easier to accomplish the integration. 4. Subtract the field found in Question 3 above from a plane wave field
E_(0)e^(ikd)
to obtain the on-axis field behind a circular block. Show that the intensity on axis behind the circular block is constant (i.e. independent of
d
) and is equal to the intensity of the initial plane wave. 5. Repeat Question 3 to find the on-axis intensity after a circular aperture in the Fresnel approximation. HINT: You can make a suitable approximation directly to the answer of Question 3 to obtain the Fresnel approximation. However, you should also perform the integration under the Fresnel approximation for the sake of gaining experience. 6. Repeat Question 3 (or Question 5) to find the on-axis intensity after a circular aperture in the Fraunhofer approximation. HINT: You can make a suitable approximation directly to the answer of Question 5 to obtain the Fraunhofer approximation. However, you should perform the integration under the Fraunhofer approximation for the sake of gaining experience.