(Solved): answer plz It is to distinguish cyclohexane and cyclohexene by IR spectroscopy. The \( =\mathrm{C}-\ ...

It is to distinguish cyclohexane and cyclohexene by IR spectroscopy. The \( =\mathrm{C}-\mathrm{H} \) stretch should appear in the spectrum of around \( \mathrm{cm}^{-1} \), which will be probably easier to see than the corresponding \( \mathrm{C}=\mathrm{C} \) around \( \mathrm{cm}^{-1} \) to distinguish cyclohexane and cyclohexene by \( \mathrm{IR} \) spectroscopy. The \( =\mathrm{C} \cdot \mathrm{H} \) stretch should appear in the around \( \mathrm{cm}^{-1} \), which will be probably easier to see than the corresponding \( \mathrm{C}=\mathrm{C} \) around \( \mathrm{cm}^{-1} \). It is Choose... to distinguish cyclohexane and cyclohexene by \( \mathrm{IR} \) spectroscopy. The \( =\mathrm{C}-\mathrm{H} \) stretch should appear in the spectrum of around \( \mathrm{cm}^{-1} \), which will be probably easier to see than the correspd It is to distinguish cyclohexane and cyclohexene bv \( \mathbb{R} \) spectroscopy. The \( =\mathrm{C}-\mathrm{H} \) stretch should appear in the spectrum of around \( \mathrm{cm}^{-1} \), which will be probably easier to see than the corresponding \( \mathrm{C}=\mathrm{C} \) around \( \mathrm{cm}^{-1} \). It is to distinguish cyclohexane and cyclohexene by \( \mathbb{R} \) spectroscopy. The \( =\mathrm{C}-\mathrm{H} \) stretch should appear in the spectrum of around \( \mathrm{cm}^{-1} \), which will be probably easier to see than the corresponding \( \mathrm{C}=\mathrm{C} \) around