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(Solved): A spring with force constant \( k=100 \mathrm{~N} / \mathrm{m} \) has two masses hanging from it ...



A spring with force constant \( k=100 \mathrm{~N} / \mathrm{m} \) has two masses hanging
from it, as drawn ( \( M=1 \mathrm{~

What is the maximum velocity of the remaining mass during its oscillation?

A spring with force constant \( k=100 \mathrm{~N} / \mathrm{m} \) has two masses hanging from it, as drawn ( \( M=1 \mathrm{~kg} \) ) (Figure 1). Without the masses, the free end of the spring (point A) is at an equilibrium distance of \( 10 \mathrm{~cm} \) below Suppose that both masses are present and the system is initially motionless. If the string connecting the two its support point. masses is suddenly cut (at point \( \mathrm{C} \) in the diagram) and the lower mass falls to the floor, find the period of the resulting oscillation of the remaining mass. Part D Find the amplitude of the motion of the remaining mass. What is the maximum velocity of the remaining mass during its oscillation?


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consider the given system. Two equal masses are attached together on a string xKMMF=kXF=2MgMF=kxMgX
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