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(Solved): A spring with a 8-kg mass and a damping constant 16 can be held stretched 1 meters beyond its natura ...



A spring with a 8-kg mass and a damping constant 16 can be held stretched 1 meters beyond its natural length by a force of 4 newtons. Suppose the spring is stretched 2 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c^(2)-4mk ? m^(2)k(g^(2))/(sec^(2)) help (numbers) Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c_(1)e^(\alpha t)+c_(2)e^(\beta t) where \alpha = (the larger of the two) help (numbers) \beta = (the smaller of the two) help (numbers) c_(1)= help (numbers) c_(2)= help (numbers)


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