A small mailbag is released from a helicopter that is descending steadily at
2.93(m)/(s)
. (a) After
5.00s
, what is the speed of the mailbag?
v=
◻
(m)/(s)
(b) How far is it below the helicopter?
d=
q,
m
(c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at
2.93(m)/(s)
?
v=
◻
(m)/(s)
d=
◻
m Need Help?
◻