(Solved): A permanent bar magnet with the north pole directed at left is placed on the left side of a copper ...

A permanent bar magnet with the north pole directed at left is placed on the left side of a copper ring. The ring is moving with a velocity \( v \) toward the left. As the ring moves across the magnet (first toward the south pole, then away from the north pole), what is the direction of the induced current in the ring when viewed from the right side of the ring? no induced current first clockwise, then counterclockwise first clockwise, then clockwise first counterclockwise, then counterclockwise first counterclockwise, then clockwise A single-turn circular loop of radius \( 0.5 \mathrm{~m} \) and negligible resistance is immersed in a uniform magnetic field that is perpendicular to the plane of the loop. The loop is connected to a \( 3 \Omega \) resistor to create a closed circuit. During a \( 0.2 \mathrm{~s} \)-time interval, the field magnitude changes uniformly from \( 0.3 \mathrm{~T} \) to \( 0.8 \mathrm{~T} \). What is the electric power that is dissipated in the resistor during this time interval? \( 14 \mathrm{~W} \) \( 6.0 \mathrm{~W} \) \( 2.5 \mathrm{~W} \) \( 0.2 \mathrm{~W} \) \( 1.3 \mathrm{~W} \)