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(Solved): A horizontal force of magnitude \( 35.8 \mathrm{~N} \) pushes a block of mass \( 4.35 \mathrm{~kg} ...




A horizontal force of magnitude \( 35.8 \mathrm{~N} \) pushes a block of mass \( 4.35 \mathrm{~kg} \) across a floor where th
A horizontal force of magnitude \( 35.8 \mathrm{~N} \) pushes a block of mass \( 4.35 \mathrm{~kg} \) across a floor where the coefficient of kinetic friction is \( 0.630 \) (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of \( 4.70 \mathrm{~m} \) across the floor? (b) During that displacement, the thermal energy of the block increases by \( 37.5 \mathrm{~J} \). What is the increase in thermal energy of the floor? (c) What is the increase in the kinetic energy of the block? (a) Number Units (b) Number Units (c) Number Units


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SOLUTION:- STEP1 Given data :- F = 35.8N mass of the block m= 4.35kg coefficient of kinetic energy ?k = .630 displacement d =4.70m thermal energy incr
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