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(Solved): A \( 50 \mathrm{~g} \) bullet is fired horizontally at one end of a \( 0.60 \mathrm{~m} \) long uni ...




A \( 50 \mathrm{~g} \) bullet is fired horizontally at one end of a \( 0.60 \mathrm{~m} \) long uniform rod of mass \( 0.50 \
A \( 50 \mathrm{~g} \) bullet is fired horizontally at one end of a \( 0.60 \mathrm{~m} \) long uniform rod of mass \( 0.50 \) \( \mathrm{kg} \), which is originally at rest and is pivoted at another end at point A in a vertical plane, as shown in Figure 9. If the angular speed of the system (bullet + rod assumed to stick together) about A just after impact is \( 4.5 \mathrm{rad} / \mathrm{s} \), what is the bullet's speed just before impact? A) \( 12 \mathrm{~m} / \mathrm{s} \) B) \( 10 \mathrm{~m} / \mathrm{s} \) C) \( 14 \mathrm{~m} / \mathrm{s} \) D) \( 17 \mathrm{~m} / \mathrm{s} \) E) \( 20 \mathrm{~m} / \mathrm{s} \)


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The bullet was let say moving with a velocity 'v', and the rod was still before the impact. Given: Just after the impact the angular velocity is equal
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