(Solved): 1.Suppose an isolated box of volume \( 2 \mathrm{~V} \) is divided into two equal compartments. \( ...

1.Suppose an isolated box of volume \( 2 \mathrm{~V} \) is divided into two equal compartments. \( \mathrm{N} \) atoms of an ideal mono-atomic gas occupy half of the container and the other half is empty as in the figure at the left. The initial temperature is \( \mathrm{T}_{\mathrm{i}} \). The partition separating the two halves of the box is removed (simply pulled out) and the system reaches equilibrium again as in the figure at the right. (a) Is this process reversible? Yes / no (b) What is the temperature after the process? Hint: No heat entered the system, and the gas did no work. (c) What is the pressure before the process? \( \mathrm{P}_{\mathrm{i}}= \) (d) What is the pressure after the process? (e) Suppose one tries to compress the gas back to volume V. Keeping the system isolated, one compresses the gas. How does the temperature after this adiabatic compression compare to the original temperature?