00:07:14A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between the patients using and not using the new drug.Let d = (hours of sleep with the new drug)-(hours of sleep without the new drug). Assume that the hours of sleep are normally distributed for the population of patients both before and after taking the new drug.PatientHours of sleep without the drug5.523456.9 2 2.2 3.763.578 93.6 2.4 4.5Hours of sleep with the new drug17.8 8.1 5 4.1 5.3 6.2 4.3 4.9 7.5Copy DataStep 2 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.